The correct answer is 3. The duty cycle is defined as the ratio of the on-time to the total time, so, in this case, the duty cycle = 2 msecs/(2 msecs + 8 msecs) = 0.20(100) = 20 percent
The correct answer is 3. The duty cycle is defined as the ratio of the on-time to the total time, so, in this case, the duty cycle = 2 msecs/(2 msecs + 8 msecs) = 0.20(100) = 20 percent